14y^2-11y-34=0

Solution for 14y^2-11y-34=0 equation:

14y^2-11y-34=0

a = 14; b = -11; c = -34;
Δ = b2-4ac
Δ = -112-4·14·(-34)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-45}{2*14}=\frac{-34}{28}
=-1+3/14
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+45}{2*14}=\frac{56}{28}
=2
$